the cipher is:
110.211.310.211 110.211.110.111.210.111 110.311.410 110.211.110.111.310 110.211.210.111.110.111 110.311.210.111.110
the question is: how much 10 and 11 x)
we have one 10 two 11 three 10 etc...
we'll get this:
101111101010111110111110111010111011111110101010101111101110101010111110101110111011111110101110
this is like the 1st step except that we always add a 1 means: one 1 one 1 one 1 etc...
so all you have to do is to remove them (1x1x1x1x1x1x1x etc...) it's just a matter of lengths :p
011000110110100101110000011010000110010101110010
see how it has become?
yes that's the original encoded binary now all what you have to do is to decode it :) and you'll get the decrypted text which is: cipher
easy isn't :)
